Find the minimum value of (y = 3x^{2} – x – 6).
-
A.
(-6frac{1}{6}) -
B.
(-6frac{1}{12}) -
C.
(-6) -
D.
(0)
Correct Answer: Option B
Explanation
(3x^{2} – x – 6 = y)
(a = 3, b = -1, c = -6)
Minimum value of x = (frac{-b}{2a} = frac{-(-1)}{6} = frac{1}{6})
(y(frac{1}{6}) = 3(frac{1}{6}^{2}) – frac{1}{6} – 6 = -6frac{1}{12})