Given that (sin x = frac{5}{13}) and (sin y = frac{8}{17}), where x and y are acute, find (cos(x+y)).
-
A.
(frac{130}{221}) -
B.
(frac{140}{221}) -
C.
(frac{140}{204}) -
D.
(frac{220}{23})
Correct Answer: Option B
Explanation
(cos(x+y) = cos xcos y – sin xsin y)
Given (sin) of an angle implies we have the value of the opposite and hypotenuse of the right-angled triangle. We find the adjacent side using Pythagoras’ theorem.
(Adj^{2} = Hyp^{2} – Opp^{2})
For triangle with angle x, (adj = sqrt{13^{2} – 5^{2}} = sqrt{144} = 12)
For triangle with angle y, (adj = sqrt{17^{2} – 8^{2}} = sqrt{225} = 15)
(therefore cos x = frac{12}{13}; cos y = frac{15}{17})
(cos(x+y) = (frac{12}{13}timesfrac{15}{17}) – (frac{5}{13}timesfrac{8}{17}) = frac{180}{221} – frac{40}{221})
= (frac{140}{221})