A body is acted upon by forces (F_{1} = (10 N, 090°)) and (F_{2} = (6 N, 180°)). Find the magnitude of the resultant force.
-
A.
11.6 N -
B.
11.7 N -
C.
11.8 N -
D.
11.9 N
Correct Answer: Option B
Explanation
(F = F cos theta i + F sin theta j) (Resolving F into its components)
(F_{1} = (10 N, 090°) = 10 cos 90 i + 10 sin 90 j)
= (10 j)
(F_{2} = (6 N, 180°) = 6 cos 180 i + 6 sin 180 j)
= (-6 i)
(R = – 6 i + 10 j)
(|R| = sqrt{(-6)^{2} + (10)^{2}})
= (sqrt{136})
= 11.7 N