If (x + 1) is a factor of the polynomial (x^{3} + px^{2} + x + 6). Find the value of p.
-
A.
-8 -
B.
-4 -
C.
4 -
D.
8
Correct Answer: Option B
Explanation
If (x + 1) is a factor, then f(-1) = 0.
((-1)^{3} + p(-1)^{2} + (-1) + 6 = 0)
(-1 + p – 1 + 6 = 0 implies p + 4 = 0)
(p = -4)