Yomi was asked to label four seats S, R, P, Q. What is the probability he labelled them in alphabetical order?
-
A.
(frac{1}{24}) -
B.
(frac{1}{6}) -
C.
(frac{2}{13}) -
D.
(frac{1}{4})
Correct Answer: Option A
Explanation
The number of arrangements for the 4 letters = (^{4}P_{4} = frac{4!}{(4 – 4)!})
(4! = 24)
Alphabetical order is just 1 of the arrangements for the letters
= (frac{1}{24})