Using the binomial expansion ((1+x)^{6} = 1 + 6x + 15x^{2} + 20x^{3} + 15x^{4} + 6x^{5} + x^{6}), find, correct to 3 dp, the value of ((1.98)^{6}).
-
A.
64.245 -
B.
61.255 -
C.
60.255 -
D.
60.245
Correct Answer: Option C
Explanation
((1.98)^{6} = (1 + 0.98)^{6} = 1 + 6(0.98) + 15(0.98)^{2} + 20(0.98)^{3} + 15(0.98)^{4} + 6(0.98)^{5} + (0.98)^{6})
(approxeq 1 + 5.88 + 14.406 + 18.823 + 13.836 + 5.424 + 0.886 )
= (60.255)