The velocity, V, of a particle after t seconds, is (V = 3t^{2} + 2t – 1). Find the acceleration of the particle after 2 seconds.
-
A.
10(ms^{-2}) -
B.
12(ms^{-2}) -
C.
14(ms^{-2}) -
D.
17(ms^{-2})
Correct Answer: Option C
Explanation
(accl = frac{mathrm d V}{mathrm d t})
(V = 3t^{2} + 2t – 1 therefore a = frac{mathrm d V}{mathrm d t} = 6t + 2)
(a text{(after 2 seconds)} = (6times 2) + 2 = 12+2 = 14ms^{-2})