The sum, (S_{n}), of a sequence is given by (S_{n} = 2n^{2} – 5). Find the 6th term.
-
A.
112 -
B.
67 -
C.
45 -
D.
22
Correct Answer: Option D
Explanation
(S_{n} = 2n^{2} – 5)
(T_{n} = S_{n} – S_{n – 1})
(T_{6} = S_{6} – S_{5})
= ((2(6^{2} – 5) – (2(5^{2} – 5) = 62 – 40 = 22)