The mean age of n men in a club is 50 years. Two men aged 55 and 63 years left the club, and the mean age reduced by 1 year. Find the value of n.
-
A.
30 -
B.
20 -
C.
18 -
D.
14
Correct Answer: Option B
Explanation
Let the sum of the men’s ages be f, so that
(frac{f}{n} = 50 …. (1))
Also, (frac{f – (55 + 63)}{n – 2} = 50 – 1 = 49 …. (2))
From (1), (f = 50n)
From (2), (f – 118 = 49(n – 2) = 49n – 98)
(f = 49n – 98 + 118 = 49n + 20)
(therefore f = 50n = 49n + 20)
(50n – 49n = n = 20)