The fourth term of a geometric sequence is 2 and the sixth term is 8. Find the common ratio.
-
A.
(pm 1) -
B.
(pm 2) -
C.
(pm 3) -
D.
(pm 4)
Correct Answer: Option B
Explanation
(T_{n} = ar^{n – 1}) (Exponential sequence)
(T_{4} = ar^{3} = 2 …. (1))
(T_{6} = ar^{5} = 8 ……(2))
Divide (2) by (1),
(frac{ar^{5}}{ar^{3}} = frac{8}{2} )
(r^{2} = 4)
(r = pm 2)