Solve (3x^{2} + 4x + 1 > 0)
-
A.
(x -
B.
(x > -1, x > -frac{1}{3}) -
C.
(x > frac{1}{3}, x -
D.
(x -1)
Correct Answer: Option B
Explanation
(3x^{2} + 4x + 1 > 0 )
(3x^{2} + 3x + x + 1 > 0)
(3x(x + 1) + 1(x + 1) > 0)
((3x + 1)(x + 1) > 0)
(3x + 1 > 0 implies 3x > -1 )
(x > -frac{1}{3})
(x + 1 > 0 implies x > -1)
(x > -1, x > -frac{1}{3})