Find the least value of the function (f(x) = 3x^{2} + 18x + 32).
-
A.
5 -
B.
4 -
C.
-3 -
D.
-2
Correct Answer: Option A
Explanation
(f(x) = 3x^{2} + 18x + 32)
(frac{mathrm d y}{mathrm d x} = 6x + 18 = 0)
(6x = -18 implies x = -3)
(f(-3) = 3(-3^{2}) + 18(-3) + 32 = 27 – 54 + 32 = 5)