A particle starts from rest and moves in a straight line such that its velocity,…

A particle starts from rest and moves in a straight line such that its velocity, v, at time t seconds is given by (v = (3t^{2} – 2t) ms^{-1}). Calculate the distance covered in the first 2 seconds.

Correct Answer: Option B

Explanation

(v(t) = (3t^{2} – 2t) ms^{-1})

(s(t) = int v(t) mathrm {d} t)

= (int (3t^{2} – 2t) mathrm {d} t = t^{3} – t^{2})

(s(2) = 2^{3} – 2^{2} = 8 – 4 = 4m)