A line is perpendicular to (3x – y + 11 = 0) and passes through the point (1, -5). Find its equation.
-
A.
3y – x -14 = 0 -
B.
3x + y + 1 = 0 -
C.
3y + x + 1 = 0 -
D.
3y + x + 14 = 0
Correct Answer: Option D
Explanation
(3x – y + 11 = 0 implies y = 3x + 11)
(Gradient = 3)
Gradient of perpendicular line = (frac{-1}{3})
(therefore frac{y – (-5)}{x – 1} = frac{-1}{3})
(3(y + 5) = 1 – x)
(3y + x + 15 – 1 = 3y + x + 14 = 0)