A force F acts on a body of mass 12kg increases its speed from 5 m/s to 35 m/s in 5 seconds. Find the value of F.
-
A.
36 N -
B.
48 N -
C.
72 N -
D.
108 N
Correct Answer: Option C
Explanation
(F = ma )
(a = frac{v – u}{t})
(therefore F = m(frac{v – u}{t}))
(F = 12(frac{35 – 5}{5}) = 12 times 6 = 72 N)