A box contains 14 white balls and 6 black balls. Find the probability of first drawing a black ball and then a white ball without replacement.
-
A.
0.21 -
B.
0.22 -
C.
0.30 -
D.
0.70
Correct Answer: Option B
Explanation
The probability of picking a black ball = (frac{6}{6 + 14} = frac{6}{20})
Probability of a white ball without replacement = (frac{14}{19})
Probability of a black ball and then white without replacement = (frac{6}{20} times frac{14}{19} = frac{21}{95} = 0.22)