A ball is thrown vertically upwards with a velocity of 15(ms^{-1}). Calculate the maximum height reached. ([g = 10ms^{-2}])
-
A.
15.25m -
B.
13.25m -
C.
11.25m -
D.
10.25m
Correct Answer: Option C
Explanation
Maximum height (H) = (frac{u^{2}}{2g})
= (frac{15^{2}}{2 times 10} = frac{225}{20})
= (11.25m)