A bag contains 2 red and 4 green sweets of the same size and shape. Two boys pick a sweet each from the box, one after the other, without replacement. What is the probability that at least a sweet with green wrapper is picked?
-
A.
(frac{1}{5}) -
B.
(frac{2}{5}) -
C.
(frac{8}{15}) -
D.
(frac{14}{15})
Correct Answer: Option D
Explanation
P(at least one green wrapper) = 1 – P(no green wrapper)
= (1 – (frac{2}{6} times frac{1}{5}))
= (1 – frac{1}{15})
= (frac{14}{15})