Find the equation of the circle centre (2. 3) which passes through the y – intercept of the line 3x – 2y + 6 = 0
Explanation
At y-intercept, 3(0) — 2y + 6 = 0 and solving for y, y = 3.
Therefore, the coordinates of y — intercept is (0, 3).
Then, r(^2) = (0 — 2)(^2) + (3 — 3)(^2) = 4. With the centre at (2, 3). the equation of the circle was (x — 2)(^2) + (y — 3)(^2) = 4 and which simplified to (x^2) – y(^2) — 4x — 6y + 9 = 0