A car moving with an initial velocity, u, travels in a straight line with a constant acceleration of 3ms(^{-2}) until it attains a velocity of 33ms(^{-1}) after 6 seconds. Calculate the distance travelled by the car.
Explanation
We find the initial velocity using the formula (v = u + at)
(33 = u + 3(6) implies 33 = u + 18)
(u = 15ms^{-1})
Distance (s = ut + frac{1}{2} at^{2})
= (15 times 6 + frac{1}{2} (3)(6^{2}))
= (90 + 54 = 144m)